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NES and SNES Mega Man password systems tend to be somewhat direct, associating each dot or panel in the password grid with a particular set of items or weapons.
The Mega Man IV password system has two features Steps 4 and 6, below that deliberately make this sort of association extremely difficult to make.
In order to follow along, it's necessary to know a little bit about the binary number system. Most significantly, Step 6 involves adding binary numbers.
Fortunately, Mega Man IV and Mega Man V use almost exactly the same system, so the same process can be used to generate passwords for each game.
In order to figure out this algorithm, I reverse-engineered the password generation routines in Mega Man IV. Then I took a look at Mega Man V's password generation routines and realized soon enough that they were the same ones.
What this means is that I'm extremely confident that the system described here covers all the passwords generated in these games, but I can't guarantee that they don't accept some password other than the ones I'm describing here.
So maybe there's still an easter egg out there somewhere Construct a sequence of 40 bits zeros and ones that describes the state of the game.
For each of the bits, if it represents a single item or battle, write down a 1 to have that item or to have finished that battle and a 0 otherwise.
If it is an item you can have in multiples, write down a binary representation of number of that item you want to have, using zeros at the beginning to fill up any bits you don't need.
The Mega Man IV password system is strict; if you try to create a password for a scenario that could never occur in the normal course of the game, that password will be incorrect.
The Mega Man V password system is somewhat more lenient. Although under normal circumstances you would only be able to get the crystals when you had access to the last four stages and you would only be able to get the Power Generator once you had all four crystals, none of that matters to the validity of your passwords.
Feel free to have the Power Generator at the beginning of the game! Certain items aren't shown above, either because you get them by having other items or because the passwords just don't keep track of them.
Here's a list of those items and how to get them:. Let's generate the "ultimate" passwords for Mega Man IV and Mega Man V, passwords that give us as many weapons, plates, items, and lives as we can carry.
This is the type of password that tends to be posted to cheat sites and incorporated into FAQs. We can create ultimate passwords for both games simultaneously if we use the following sequence:.
If we use this sequence for Mega Man V, we are giving ourselves an extra item that doesn't do anything and that we could never have obtained normally.
Don't bother looking for it; it doesn't appear on the status screen. If we wanted to get a "normal" ultimate password for Mega Man V, we would need to use the following sequence instead:.
For simplicity's sake, we'll just keep going with the first sequence rather than choosing a separate one for each game.
Besides helping chunk the sequence up into neat slices, this will be a bit of a help in Steps 3 and 6. To get the first value, count the number of ones in the sequence, find the remainder when dividing that number by 8, and represent that remainder as a three-bit binary number.
We'll call this value the three-bit checksum. To get the second value, interpret every four bits of the sequence as a binary number, add up all of those numbers, find the remainder when dividing the total by 32, and represent that remainder as a five-bit binary number.
We'll call this value the five-bit checksum. Finding the remainder when dividing a number by 8 is the same as looking at just the last three bits of that number's binary representation, and finding the remainder when dividing by 32 is the same as looking at just the last five bits, so we can take remainders or crop off bits interchangeably in each of the above processes without it making a difference.
We have 26 ones in our sequence. Since the remainder when dividing 26 by 8 is 2, our three-bit checksum is To get our five-bit checksum, we first add up the binary values represented by every four bits in our sequence:.
Our five-bit checksum is 2, so we slide each bit in the sequence 2 spaces to the right and move the 2 bits that "fall off" back to the beginning:.
Modify the sequence by summing each byte with its respective byte from the following sequence, performing the addition in binary:. Whenever one of these sums has nine bits, crop the leftmost bit off so that the sum fits back into the sequence.
This is the same as taking the remainder when dividing the sum by